how about this:

find . -type f -name '*.mp4' -exec bash -c 'ffmpeg -i "$0" "${0/%mp4/mp3}"' '{}' \;

i've had this for ages (copied from some gist someplace), still works fine afaik.

I usually do this, which looks like it was suggested above...

for i in *.mp3; do ffmpeg -i "$i" "${i%.*}.opus"; done

Btw, this works for changing to others, such as flac, or ogg, etc...

I don't think there are many ways to keep the video format though if this is what you after...

find . -type f -name '*.mp4' -exec bash -c 'ffmpeg -i "$0" "${0/%mp4/mp3}"' '{}' \;

i've had this for ages (copied from some gist someplace), still works fine afaik.

for X in *.mp4; do ffmpeg -i "$X" "${X%.mp4}".mp3; done

EDIT: moved second close quote to before the dot. Meh.

Thanks for the extra info though, this kind of thread gets read by more than those who post them, so any extra is always welcome.

for X in *.mp4;do ffmpeg -i "$X" "$X".mp3;done

Unless you actually want to remove the spaces anyway.

To remove the spaces with bash use

for f in *\ *.mp3; do mv "$f" "${f// /_}" ; done

The "${f// /_}" bit uses bash's parameter expansion mechanism to search and replace the given pattern.

See https://wiki.bash-hackers.org/syntax/pe … nd_replace for more on this. It won't work with /bin/sh though.

EDIT: oh, hello Keith. Didn't realise it was you :-)

I have a load of mp4 files with spaces in their names, the first line replaces the spaces with _ so that the second line can convert them to mp3.

#!/bin/sh

for f in *; do mv "$f" `echo $f | tr ' ' '_'`; done

for X in *.mp4;do ffmpeg -i $X $X.mp3;done